Exercise · ZW-DISJUNCTION-010 · ★★★ Advanced
By De Morgan, ¬(P∨Q) is equivalent to...
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- B. ¬P∧¬Q
Exercise · ZW-DISJUNCTION-010 · ★★★ Advanced
Choose one option.
By De Morgan, \(\neg(P\lor Q)\equiv\neg P\land\neg Q\): the negation of a disjunction is the conjunction of the negations.
Given propositions \(P\) and \(Q\), their inclusive disjunction is the proposition \(P\lor Q\).