Exercise · ZW-PROBABILITY-DENSITY-FUNCTION-010 · ★★★ Advanced

\(f(x)=c(1-x^2)\) on \([-1,1]\) and 0 elsewhere is a density. What is \(c\)?

Choose one option.

Show answer
  • D. \(\tfrac34\)

Explanation

\(\int_{-1}^{1}(1-x^2)\,dx=2-\tfrac23=\tfrac43\), and \(c\cdot\tfrac43=1\) gives \(c=\tfrac34\). The option \(\tfrac43\) is the unnormalized area.

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Review the concept: Probability density function

The density function \(f\) of a continuous random variable \(X\) is a nonnegative function such that the area under its graph over an interval is the probability \(P\) that \(X\) falls in it.

\[P(a\le X\le b)=\int_a^b f(x)\,dx\]

More practice problems: probability density function

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