Exercise · ZW-CHINESE-REMAINDER-THEOREM-007 · ★★☆ Intermediate
Solve \(x\equiv 1 \pmod 5\) and \(x\equiv 2 \pmod 7\). What is the smallest positive integer \(x\) satisfying both?
Choose one option.
Show answer
- B. \(16\)
Exercise · ZW-CHINESE-REMAINDER-THEOREM-007 · ★★☆ Intermediate
Choose one option.
The number \(16\) satisfies \(16\equiv 1\pmod 5\) and \(16\equiv 2\pmod 7\). The option \(30\) satisfies the second congruence but not the first, since \(30\equiv 0\pmod 5\).
The Chinese remainder theorem states that a system of linear congruences with pairwise coprime moduli has a unique solution modulo the product of those moduli.
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