Exercise · ZW-CONTINUED-FRACTION-007 · ★★☆ Intermediate
Compute the convergent \( p_2/q_2 \) of the continued fraction \( [4; 2, 6, 7] \).
Choose one option.
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- D. 58/13
Exercise · ZW-CONTINUED-FRACTION-007 · ★★☆ Intermediate
Choose one option.
With \( a_2 = 6 \) the recurrences give \( p_2 = 6 \cdot 9 + 4 = 58 \) and \( q_2 = 6 \cdot 2 + 1 = 13 \). The option 9/2 is the previous convergent, and 415/93 is the full value.
A continued fraction is an expression of the form a₀ + 1/(a₁ + 1/(a₂ + ...)), where a₀ is an integer and the remaining terms aᵢ are positive integers.