Exercise · ZW-DIVISIBILITY-003 · ★☆☆ Basic

If \(a\mid b\) and \(b\mid c\), what always follows?

Choose one option.

Show answer
  • A. \(a\mid c\)

Explanation

If \(b=ak\) and \(c=bj\), then \(c=a(kj)\), so \(a\mid c\). Divisibility is transitive but not symmetric.

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Review the concept: Divisibility

An integer \(a\neq0\) divides an integer \(b\), written \(a\mid b\), when \(b\) is an integer multiple of \(a\).

\[a\mid b\iff b=ak\ \text{for some } k\in\mathbb{Z}\]

More practice problems: divisibility

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