Exercise · ZW-DIVISOR-FUNCTIONS-009 · ★★★ Advanced
Let \( n=2^4\cdot 3^2 \). Compute \( \tau(n^2) \) and compare it with \( \tau(n)^2 \). Are they equal?
Choose one option.
Show answer
- B. No, \( \tau(n^2)=45 \) and \( \tau(n)^2=225 \)
Exercise · ZW-DIVISOR-FUNCTIONS-009 · ★★★ Advanced
Choose one option.
We have \( \tau(n)=5\cdot 3=15 \), so \( \tau(n)^2=225 \). Since \( n^2=2^8\cdot 3^4 \), \( \tau(n^2)=9\cdot 5=45 \), so they are not equal. The option giving 15 for \( \tau(n^2) \) forgets to double the exponents.
The divisor functions \( \sigma_k(n) \) and \( \tau(n) \) give, respectively, the sum of the \( k \)-th powers and the number of positive divisors of an integer \( n \geq 1 \).