Exercise · ZW-DIVISOR-FUNCTIONS-009 · ★★★ Advanced

Let \( n=2^4\cdot 3^2 \). Compute \( \tau(n^2) \) and compare it with \( \tau(n)^2 \). Are they equal?

Choose one option.

Show answer
  • B. No, \( \tau(n^2)=45 \) and \( \tau(n)^2=225 \)

Explanation

We have \( \tau(n)=5\cdot 3=15 \), so \( \tau(n)^2=225 \). Since \( n^2=2^8\cdot 3^4 \), \( \tau(n^2)=9\cdot 5=45 \), so they are not equal. The option giving 15 for \( \tau(n^2) \) forgets to double the exponents.

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Review the concept: Divisor functions

The divisor functions \( \sigma_k(n) \) and \( \tau(n) \) give, respectively, the sum of the \( k \)-th powers and the number of positive divisors of an integer \( n \geq 1 \).

\[\sigma_k(n)=\sum_{d\mid n} d^{k},\quad \tau(n)=\sigma_0(n)\]

More practice problems: divisor functions

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