Exercise · ZW-EULER-S-METHOD-005 · ★☆☆ Basic
How many steps does Euler need to go from \(t=0\) to \(t=1\) with \(h=0.25\)?
Choose one option.
A \(3\) B \(5\) C \(0.25\) D \(4\)
Show answer
← Back to the question
Explanation The number of steps is \((b-a)/h=1/0.25=4\). Miscounting one step less gives three, and forgetting the initial step leads to five.
Euler's method approximates the solution of an initial value problem \(y'=f(t,y)\), \(y(t_0)=y_0\), advancing in steps of size \(h\) using the slope at the current point.
\[y_{n+1}=y_n+h\,f(t_n,y_n)\]
More practice problems: euler's method ZW-EULER-S-METHOD-001 For the problem y'=2t, y(0)=0, what is the Euler formula for y_n+1?ZW-EULER-S-METHOD-002 What is the global convergence order of Euler's method?ZW-EULER-S-METHOD-003 For y'=y, y(0)=1, what is the value of y_1 with h=0.5?ZW-EULER-S-METHOD-004 What is the value of f(t,y) in the problem y'=t+y?ZW-EULER-S-METHOD-006 Apply one Euler step to y'=t-y, y(0)=2, with h=0.1. What is y_1?ZW-EULER-S-METHOD-007 With y'=-2y, y(0)=1 and h=0.1, what is y_2?ZW-EULER-S-METHOD-008 For y'=t^2, y(1)=0, with h=0.5, what is y_1 at t=1.5?ZW-EULER-S-METHOD-009 With y'=y, y(0)=1 and h=0.2, what is the approximation y_2 to y(0.4)?