Exercise · ZW-EULERIAN-CYCLE-009 · ★★★ Advanced
From \(K_5\) the 4 edges of a cycle \(1\text{-}2\text{-}3\text{-}4\text{-}1\) are removed. What graph remains?
Choose one option.
A It is Eulerian and has 10 edges B It is Eulerian and has 6 edges C It is not connected D It is connected but has odd-degree vertices
Show answer B. It is Eulerian and has 6 edges
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Explanation There remain \(10-4=6\) edges. Vertices 1 to 4 drop from degree 4 to 2, vertex 5 keeps degree 4, and the graph stays connected (5 is adjacent to all). All degrees are even.
An Eulerian cycle of a graph \(G=(V,E)\) is a cycle that traverses every edge of \(G\) exactly once.
\[G\text{ connected and }\deg(v)\text{ even }\forall v\in V\iff\text{Eulerian cycle exists}\]
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