Exercise · ZW-FINITE-DIFFERENCES-FOR-DERIVATIVES-010 · ★★☆ Intermediate

With \(f(0)=1\), \(f(0.2)=1.44\) and \(f(-0.2)=0.84\), what is the centered approximation of \(f'(0)\) with \(h=0.2\)?

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  • A. \(1.5\)

Explanation

With the centered formula, \(\frac{1.44-0.84}{2\cdot 0.2}=\frac{0.6}{0.4}=1.5\); the other values come from using the forward or backward formula or dividing by 2 instead of \(2h\).

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Review the concept: Finite differences for derivatives

Finite differences are approximations of the derivatives of a function \(f\) from its values at discrete points separated by a step \(h\). They turn differential problems into algebraic systems that a computer can solve.

\[f'(x)\approx \frac{f(x+h)-f(x)}{h}\]

More practice problems: finite differences for derivatives

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