Exercise · ZW-FIXED-POINT-ITERATION-009 · ★★☆ Intermediate

If \( g(x) = \frac{x}{2} + 1 \), what is the limit of \( x_n \) starting from any \( x_0 \)?

Choose one option.

Show answer
  • D. \( 2 \)

Explanation

The fixed point satisfies \( p = \frac{p}{2} + 1 \), so \( p = 2 \). Since \( |g'| = \frac{1}{2} < 1 \), the sequence converges to \( 2 \). The option \( 1 \) is the constant term, not the fixed point.

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Review the concept: Fixed-point iteration

Iterative method that approximates a solution of the equation \( x = g(x) \) by generating the sequence \( x_{n+1} = g(x_n) \) from an initial value \( x_0 \).

\[x_{n+1} = g(x_n), \quad |g'(p)| < 1 \Rightarrow \text{convergencia local}\]

More practice problems: fixed-point iteration

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