The 4 vertices of \(K_4\) are mutually adjacent, so they use 4 different colors and \(G\) needs at least 4. But it may need more (for example \(K_5\)): it cannot be guaranteed to be exactly 4.
A proper coloring \(c\) with \(k\) colors of a graph \(G=(V,E)\) assigns to each vertex one of the colors \(1,\dots,k\) so that no two adjacent vertices share a color.
\[c:V\to\{1,\dots,k\},\qquad c(u)\neq c(v)\ \text{ if } \{u,v\}\in E\]