Exercise · ZW-LOCAL-AND-GLOBAL-MINIMA-OF-CONVEX-FUNCTIONS-006 · ★★☆ Intermediate

Let \(f(x)=(x-2)^2+1\) on \([0,5]\). What is the global minimum and where is it attained?

Choose one option.

Show answer
  • C. 1 at x=2

Explanation

The term \((x-2)^2\) is minimal at \(x=2\), inside the interval, giving value 1. The option with value 1 at x=0 forgets that f(0)=5, not 1.

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Review the concept: Local and global minima of convex functions

A local minimum of a function is a point where no sufficiently small neighborhood contains smaller values, while a global minimum is a point where the function attains the lowest value over its entire domain.

\[f(x^*) \le f(x) \quad \forall x \in \mathrm{dom}\, f\]

More practice problems: local and global minima of convex functions

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