Exercise · ZW-MODULAR-CONGRUENCE-007 · ★★☆ Intermediate
Solve \(3x\equiv4\pmod7\) with \(0\le x\le6\).
Choose one option.
Show answer
- C. 6
Exercise · ZW-MODULAR-CONGRUENCE-007 · ★★☆ Intermediate
Choose one option.
Trying values: \(3\cdot6=18=2\cdot7+4\), so \(x=6\). No other residue works: \(3\cdot5\equiv1\), \(3\cdot4\equiv5\), \(3\cdot2\equiv6\).
Two integers \(a\) and \(b\) are congruent modulo a positive integer \(m\) if \(m\) divides their difference; equivalently, they leave the same remainder when divided by \(m\).