Exercise · ZW-NEWTON-S-METHOD-FOR-OPTIMIZATION-008 · ★★☆ Intermediate

For \(f(x)=e^x-2x\) on \(\mathbb{R}\), what is \(x_1\) starting from \(x_0=0\)?

Choose one option.

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  • D. \(x_1=1\)

Explanation

Here \(f'(x)=e^x-2\) and \(f''(x)=e^x\), so \(f'(0)=-1\), \(f''(0)=1\), and \(x_1=0-(-1)/1=1\). The other options come from flipping the sign or mixing up the second derivative.

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Review the concept: Newton's method for optimization

Newton's method for optimization is an iterative algorithm that seeks a critical point of a differentiable function \(f:\mathbb{R}^n\to\mathbb{R}\) using the gradient \(\nabla f\) and the Hessian \(H_f\).

\[x_{k+1}=x_k-H_f(x_k)^{-1}\nabla f(x_k)\]

More practice problems: newton's method for optimization

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