Exercise · ZW-NORMAL-DISTRIBUTION-005 · ★★☆ Intermediate

If \(Z\) is standard normal, what is \(f_Z(0)\), the height of the density at 0?

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  • B. \(\dfrac{1}{\sqrt{2\pi}}\)

Explanation

With \(\mu=0\), \(\sigma=1\) and \(x=0\) the exponent is 0, leaving \(1/\sqrt{2\pi}\approx0.399\).

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Review the concept: Normal distribution

A normal variable is a continuous variable with density \(f\) shaped like a symmetric bell, determined by its mean \(\mu\) and its standard deviation \(\sigma\).

\[f(x)=\dfrac{1}{\sigma\sqrt{2\pi}}\,e^{-\frac{(x-\mu)^2}{2\sigma^2}}\]

More practice problems: normal distribution

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