Exercise · ZW-PERMUTATIONS-AND-COMBINATIONS-005 · ★★☆ Intermediate

From 5 women and 4 men a committee of 3 is chosen at random. What is the probability it has 2 women and 1 man?

Choose one option.

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  • B. \(\frac{10}{21}\)

Explanation

Favorable: \(\binom{5}{2}\binom{4}{1}=40\); possible: \(\binom{9}{3}=84\). Probability \(\frac{40}{84}=\frac{10}{21}\).

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Review the concept: Permutations and combinations

A permutation \(P(n,k)\) is an ordered arrangement of \(k\) elements from a set of \(n\); a combination \(\binom nk\) is a selection in which order does not matter.

\[P(n,k)=\frac{n!}{(n-k)!},\quad \binom{n}{k}=\frac{n!}{k!\,(n-k)!}\]

More practice problems: permutations and combinations

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