Exercise · ZW-PRIMITIVE-ROOT-010 · ★★★ Advanced

Give a counterexample showing that not every integer coprime to \(n\) is a primitive root, taking \(n=11\) and computing the order of 10.

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  • B. 2

Explanation

Since \(10\equiv -1 \pmod{11}\), \(10^2\equiv 1\), so its order is 2, far from \(\varphi(11)=10\).

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Review the concept: Primitive root

A primitive root modulo \(n\) is an integer \(g\) whose multiplicative order modulo \(n\) equals \(\varphi(n)\), so that its powers run through all residues coprime to \(n\).

\[\operatorname{ord}_n(g)=\varphi(n)\]

More practice problems: primitive root

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