Exercise · ZW-SIMPSON-S-RULE-007 · ★★☆ Intermediate

Using the simple Simpson's rule, what is the approximate value of \(\int_0^1 e^x\,dx\)?

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  • C. \(\approx 1.719\)

Explanation

With \(h=0.5\), \(f(0)=1\), \(f(0.5)\approx 1.6487\), and \(f(1)\approx 2.7183\), the formula gives \(\frac{1}{6}(1+4\cdot1.6487+2.7183)\approx 1.7189\).

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Review the concept: Simpson's rule

Simpson's rule is a numerical quadrature method that approximates \(\int_a^b f(x)\,dx\) by integrating a quadratic polynomial that interpolates \(f\) at \(a\), \(\frac{a+b}{2}\), and \(b\).

\[\int_a^b f(x)\,dx \approx \frac{h}{3}[f(x_0)+4f(x_1)+f(x_2)], h=\frac{b-a}{2}\]

More practice problems: simpson's rule

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