Exercise · ZW-VARIANCE-001 · ★☆☆ Basic

\(X\) takes the values 0, 1 and 2 with probabilities 0.2, 0.5 and 0.3 (so \(E[X]=1.1\)). Compute \(\operatorname{Var}(X)\).

Choose one option.

Show answer
  • B. \(0.49\)

Explanation

\(E[X^2]=0.5+1.2=1.7\) and \(\operatorname{Var}(X)=1.7-1.1^2=0.49\). The 1.7 forgets to subtract \((E[X])^2\).

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Review the concept: Variance

The variance \(\operatorname{Var}(X)\) of a random variable \(X\) measures how spread out its values are around its expectation \(E\): it is the expected value of the squared deviation.

\[\operatorname{Var}(X)=E\big[(X-E[X])^2\big]\]

More practice problems: variance

ZW-VARIANCE-002 →