Lebesgue integral · Definition

Measurable function

measure theory and integrationlebesgue integral

Measurability lets us define Lebesgue integrals without partitioning the range. It is a necessary requirement: without it the Lebesgue integral is not defined.

Definition

A function f: X → ℝ is measurable with respect to a σ-algebra \(\mathcal{A}\) on X if the preimage \(f^{-1}(B)\) belongs to \(\mathcal{A}\) for every Borel set B of ℝ.

\[f^{-1}(B)\in\mathcal{A}\ \forall B\in\mathcal{B}(\mathbb{R})\]

It suffices to check the condition on a generating family of Borel sets, such as intervals \((a,\infty)\), and continuous functions are always measurable with respect to the Borel σ-algebra. Sums, products and pointwise limits of measurable functions remain measurable.

Let \(f(x)=x^2\) on \(\mathbb{R}\) with the Borel σ-algebra. Since \(\{x: x^2>a\}\) is a union of open intervals for each \(a\), checking that family is enough to conclude that f is measurable.

A typical mistake is checking only a few specific Borel sets and concluding measurability; one must use a generator of the σ-algebra. Another error is confusing measurability with continuity, which is only a sufficient condition.

Think about it

Why is checking that \(f^{-1}((a,\infty))\) is measurable for a single \(a\) not enough to conclude that f is measurable?

Because the definition requires \(f^{-1}(B)\in\mathcal{A}\) for every Borel B, and one interval does not generate the whole Borel σ-algebra, so a single isolated check does not determine measurability.

Exercises 10

References

  • Gerald B. Folland, Real Analysis: Modern Techniques and Their Applications, 2nd edition, Wiley, 1999.
  • H. L. Royden, P. M. Fitzpatrick, Real Analysis, 4th edition, Pearson, 2010.