Metric spaces · Definition

Open ball

topologymetric spaces

Before you start you need to know

The open ball is the basic unit of «near a point»: it defines open sets and, from them, limits and continuity.

Definition

The open ball \(B(x,r)\) with center \(x\) and radius \(r>0\) in a metric space \((X,d)\) is the set of points of \(X\) whose distance to \(x\) is less than \(r\).

\[B(x,r)=\{\,y\in X : d(x,y)

In the usual \(\mathbb{R}\), \(B(x,r)\) is the interval \((x-r,x+r)\); in Euclidean \(\mathbb{R}^2\), a disc without its circle. The inequality is strict, so points at distance exactly \(r\) are outside. And always \(x\in B(x,r)\), because \(d(x,x)=0<r\): no ball is empty.

The shape of the ball depends on the metric. With the max distance, \(B((0,0),1)\) is the square \((-1,1)^2\); with the taxicab one, a rhombus of area \(2\); with the discrete one, \(B(x,1)=\{x\}\) and \(B(x,r)=X\) if \(r>1\). So always keep in mind which \(d\) is in use.

A property used constantly: if \(y\in B(x,r)\) and \(s=r-d(x,y)>0\), then \(B(y,s)\subseteq B(x,r)\). It follows from the triangle inequality: if \(d(y,z)<s\), then \(d(x,z)\le d(x,y)+d(y,z)<r\). In other words, from any point of a ball you can take a small step without leaving it.

Two balls may intersect, but the intersection of two balls contains a ball around each of its points, thanks to the previous property. This is exactly what is needed to turn balls into the base of a topology.

Think about it

In the usual \(\mathbb{R}\), when is \(B(a,r)\subseteq B(b,s)\)?

When \((a-r,a+r)\subseteq(b-s,b+s)\), that is, \(|a-b|+r\le s\).

Can a ball with a large radius have a single point?

Yes, if the radius is small relative to the distances in the space: in the discrete metric, \(B(x,1)=\{x\}\). With radius larger than 1 it would be the whole space.

Exercises 10

References

  • James R. Munkres, Topology, 2nd edition, Pearson, 2000. §20
  • Bert Mendelson, Introduction to Topology, 3rd edition, Dover Publications, 1990. cap. 2