The critical point \((0,0)\) gives \(0\) (the minimum). On the boundary \(x^2=4-y^2\), so \(f=4+y^2\) with \(-2\le y\le2\); its largest value is \(8\) at \((0,\pm2)\).
The absolute extrema of a function \(f\) on a closed, bounded region \(D\) are the minimum \(m\) and the maximum \(M\) of the values \(f\) takes on \(D\).
\[m=\min_{D} f,\qquad M=\max_{D} f\]
More practice problems: absolute extrema on a region