Vectors and curves in space · Definition

Lines and planes in space

multivariable calculusanalytic geometry

Before you start you need to know

These are the linear objects of \(\mathbb R^3\) and the approximation that curves and curved surfaces will reduce to when we differentiate.

Definition

A line in space is determined by a point \(\mathbf r_0\) and a direction vector \(\mathbf d\); a plane, by a point \(\mathbf r_0\) and a normal vector \(\mathbf n\) perpendicular to it.

\[\begin{aligned}\mathbf r(t)&=\mathbf r_0+t\,\mathbf d\\\mathbf n\cdot(\mathbf r-\mathbf r_0)&=0\end{aligned}\]

A line is described as a motion: it starts at \(\mathbf r_0\) and moves in direction \(\mathbf d\) at the pace of the parameter \(t\). Separating coordinates gives the parametric equations \(x=x_0+td_1\), \(y=y_0+td_2\), \(z=z_0+td_3\). Two points \(P\) and \(Q\) suffice: the direction vector is \(Q-P\). Two lines in space can be parallel, meet, or be skew, that is, non-parallel with no common point, which is impossible in the plane.

A plane is described as a condition: its points are those for which \(\mathbf r-\mathbf r_0\) is perpendicular to \(\mathbf n\). With \(\mathbf n=\langle a,b,c\rangle\) it expands to \(ax+by+cz=d\); for example, the plane through \((1,2,3)\) with normal \(\langle2,-1,4\rangle\) is \(2x-y+4z=12\). The coefficients of the variables are thus the components of the normal.

When the data are three points or two directions, the normal comes from the cross product of two vectors in the plane. Two planes are parallel if their normals are proportional; otherwise they meet in a line whose direction is the cross product of the normals. A line and a plane are perpendicular when the direction vector is proportional to the normal.

To find where a line meets a plane, substitute its parametric equations into the plane equation and solve for \(t\). This pair of objects returns as soon as we differentiate: the tangent plane to a surface and the tangent line to a curve are their best linear approximation.

Think about it

How many points are needed to determine a plane, and what happens if the three are collinear?

Three non-collinear points determine a plane. If they are collinear, the two vectors they form are parallel, their cross product is \(\mathbf 0\) and no normal results: infinitely many planes contain them.

Exercises 10

What comes next

References

  • James Stewart, Daniel K. Clegg, Saleem Watson, Calculus: Early Transcendentals, 9th edition, Cengage, 2021. §12.5
  • Jerrold E. Marsden, Anthony Tromba, Vector Calculus, 6th edition, W. H. Freeman, 2012. §1.3
  • Joel Hass, Christopher Heil, Przemyslaw Bogacki, Maurice D. Weir, George B. Thomas Jr., Thomas' Calculus, 15th edition, Pearson, 2023. §12.5