Vectors and curves in space · Definition
Lines and planes in space
Before you start you need to know
These are the linear objects of \(\mathbb R^3\) and the approximation that curves and curved surfaces will reduce to when we differentiate.
Definition
A line in space is determined by a point \(\mathbf r_0\) and a direction vector \(\mathbf d\); a plane, by a point \(\mathbf r_0\) and a normal vector \(\mathbf n\) perpendicular to it.
A line is described as a motion: it starts at \(\mathbf r_0\) and moves in direction \(\mathbf d\) at the pace of the parameter \(t\). Separating coordinates gives the parametric equations \(x=x_0+td_1\), \(y=y_0+td_2\), \(z=z_0+td_3\). Two points \(P\) and \(Q\) suffice: the direction vector is \(Q-P\). Two lines in space can be parallel, meet, or be skew, that is, non-parallel with no common point, which is impossible in the plane.
A plane is described as a condition: its points are those for which \(\mathbf r-\mathbf r_0\) is perpendicular to \(\mathbf n\). With \(\mathbf n=\langle a,b,c\rangle\) it expands to \(ax+by+cz=d\); for example, the plane through \((1,2,3)\) with normal \(\langle2,-1,4\rangle\) is \(2x-y+4z=12\). The coefficients of the variables are thus the components of the normal.
When the data are three points or two directions, the normal comes from the cross product of two vectors in the plane. Two planes are parallel if their normals are proportional; otherwise they meet in a line whose direction is the cross product of the normals. A line and a plane are perpendicular when the direction vector is proportional to the normal.
To find where a line meets a plane, substitute its parametric equations into the plane equation and solve for \(t\). This pair of objects returns as soon as we differentiate: the tangent plane to a surface and the tangent line to a curve are their best linear approximation.
Think about it
How many points are needed to determine a plane, and what happens if the three are collinear?
Three non-collinear points determine a plane. If they are collinear, the two vectors they form are parallel, their cross product is \(\mathbf 0\) and no normal results: infinitely many planes contain them.
Exercises 10
- What is the equation of the plane through \((1,2,3)\) with normal vector \(\langle2,-1,4\rangle\)?
- A line passes through \((1,0,2)\) with direction \(\langle3,-1,4\rangle\). What are its parametric equations?
- What is a direction vector of the line through \((1,2,3)\) and \((4,0,5)\)?
- What is the equation of the plane through \((1,0,0)\), \((0,1,0)\) and \((0,0,1)\)?
- Which of the following points lies on the plane \(x+2y-z=4\)?
- Which of the planes is parallel to \(x-2y+3z=5\)?
- At which point does the line \((1+t,\,2-t,\,3+2t)\) meet the plane \(x+y+z=10\)?
- What is the relation between the line \((1,1,1)+t\langle2,-1,3\rangle\) and the plane \(4x-2y+6z=5\)?
- What is the equation of the plane through the origin containing the directions \(\langle1,2,0\rangle\) and \(\langle0,1,3\rangle\)?
- The lines \((1,0,0)+t\langle1,1,0\rangle\) and \((0,0,1)+s\langle0,1,2\rangle\) are not parallel. Do they meet?
What comes next
References
- James Stewart, Daniel K. Clegg, Saleem Watson, Calculus: Early Transcendentals, 9th edition, Cengage, 2021. §12.5
- Jerrold E. Marsden, Anthony Tromba, Vector Calculus, 6th edition, W. H. Freeman, 2012. §1.3
- Joel Hass, Christopher Heil, Przemyslaw Bogacki, Maurice D. Weir, George B. Thomas Jr., Thomas' Calculus, 15th edition, Pearson, 2023. §12.5