Exercise · ZW-BINOMIAL-DISTRIBUTION-001 · ★☆☆ Basic

A fair coin is tossed 4 times. What is the probability of getting exactly 2 heads?

Choose one option.

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  • C. \(\tfrac38\)

Explanation

There are \(\binom42=6\) ways to place the 2 heads and each has probability \((1/2)^4\), so \(P=6/16=3/8\). Forgetting the binomial coefficient gives \(1/16\).

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Review the concept: Binomial distribution

A binomial variable \(X\) counts the successes \(k\) in \(n\) independent Bernoulli trials with the same success probability \(p\); \(P(X=k)\) is the probability of getting \(k\) successes.

\[P(X=k)=\binom{n}{k}p^{k}(1-p)^{n-k},\quad k=0,1,\dots,n\]

More practice problems: binomial distribution

ZW-BINOMIAL-DISTRIBUTION-002 →