Exercise · ZW-CAUCHY-GOURSAT-THEOREM-001 · ★☆☆ Basic

Compute \(\displaystyle\oint_{|z|=1}(3z^2-2z+5)\,dz\), with the circle traversed once.

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  • C. \(0\)

Explanation

The polynomial is entire (holomorphic on all of \(\mathbb{C}\)), so the Cauchy-Goursat theorem gives \(0\) with no computation.

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Review the concept: Cauchy-Goursat theorem

The Cauchy-Goursat theorem says that, if \(f\) is holomorphic on a simply connected open set \(D\), its integral over any closed contour \(C\) contained in \(D\) is zero.

\[\oint_C f(z)\,dz=0\]

More practice problems: cauchy-goursat theorem

ZW-CAUCHY-GOURSAT-THEOREM-002 →