Complex integration · Definition

Curve and contour

complex analysiscomplex integration

Before you start you need to know

To integrate in the plane we first need to say where we walk: curves and contours are those paths, and everything that follows in complex integration is computed on them.

Definition

A smooth curve \(\gamma\) is a function from a real interval \([a,b]\) into \(\mathbb{C}\) with continuous, nonzero derivative; a contour is a finite chain of smooth curves joined end to end.

\[\gamma(t)=x(t)+i\,y(t),\qquad a\le t\le b\]

A curve is described by a parametrization \(\gamma(t)=x(t)+iy(t)\): each value of the parameter \(t\) gives a point of the plane and, as \(t\) grows, the point moves and leaves a directed trajectory. The same trajectory has many parametrizations; for example \(\gamma(t)=(1-t)+it\) with \(0\le t\le1\) and \(\tilde\gamma(s)=(1-s^2)+is^2\) with \(0\le s\le1\) trace the same segment from \(1\) to \(i\).

The derivative \(\gamma'(t)=x'(t)+iy'(t)\) is the velocity vector. Requiring it to be continuous and nonzero guarantees a tangent line at every point and rules out cusps and stops. The length of the curve is \(L=\int_a^b|\gamma'(t)|\,dt\); for \(\gamma(t)=e^{it}\), \(0\le t\le2\pi\), it gives \(2\pi\).

A contour allows corners: it is a sequence \(\gamma_1,\dots,\gamma_n\) of smooth curves where the end of each is the start of the next. The boundary of a rectangle, with four sides, is the typical example. It is called closed if the last point equals the first, and simple if it does not cross itself, except at the endpoints of a closed contour.

Every curve has an opposite \(-\gamma\), which traces the same points in the reverse direction, for example \(-\gamma(t)=\gamma(a+b-t)\). Simple closed contours are positively oriented (counterclockwise) by convention. In the next concept, the contour integral will use exactly \(\gamma\) and \(\gamma'\) to turn an integral over the path into an ordinary real integral.

Think about it

Give two different parametrizations of the segment from \(0\) to \(1\).

For example \(\gamma(t)=t\) with \(0\le t\le1\) and \(\tilde\gamma(s)=s^2\) with \(0\le s\le1\); both trace the same segment in the same direction.

Why is \(\gamma(t)=t^2+it^2\) on \([-1,1]\) not a smooth curve?

Because \(\gamma'(t)=2t(1+i)\) vanishes at \(t=0\); also the curve goes down and back up, passing twice through the same points.

Exercises 10

What comes next

References

  • Elias M. Stein, Rami Shakarchi, Complex Analysis, 1st edition, Princeton University Press, 2003. Cap. 1, §2.1
  • James Ward Brown, Ruel V. Churchill, Complex Variables and Applications, 9th edition, McGraw-Hill, 2014. §38–39
  • Lars V. Ahlfors, Complex Analysis, 3rd edition, McGraw-Hill, 1979. Cap. 4, §1.1