Exercise · ZW-CHANGE-OF-BASIS-008 · ★★☆ Intermediate
Let \(T(x)=Ax\) with \(A=\begin{pmatrix}1&2\\0&3\end{pmatrix}\) and \(B=\{(1,0),(1,1)\}\). What is the matrix \([T]_B\)?
Choose one option.
A \(\begin{pmatrix}1&4\\0&3\end{pmatrix}\) B \(\begin{pmatrix}1&3\\0&3\end{pmatrix}\) C \(\begin{pmatrix}1&0\\0&3\end{pmatrix}\) D \(\begin{pmatrix}1&-1\\0&3\end{pmatrix}\)
Show answer C. \(\begin{pmatrix}1&0\\0&3\end{pmatrix}\)
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Explanation \([T]_B=P^{-1}AP\) with \(P=\begin{pmatrix}1&1\\0&1\end{pmatrix}\). Directly: \(T(1,0)=(1,0)=1\,b_1\) and \(T(1,1)=(3,3)=3\,b_2\), so \(b_1\) stays fixed and \(b_2\) is multiplied by \(3\).
The change of basis \(P\) is the passage from a vector's coordinates with respect to a basis \(B\) to its coordinates with respect to another basis \(B'\) of the same space.
\[[x]_{B'}=P_{B'\leftarrow B}\,[x]_B\]
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