Exercise · ZW-CHANGE-OF-VARIABLES-IN-MULTIPLE-INTEGRALS-010 · ★★★ Advanced

Find the area of the region \(1\le xy\le2,\ 1\le y/x\le2\) using \(u=xy,\ v=y/x\) (positive quadrant).

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  • A. \(\tfrac{\ln2}{2}\)

Explanation

From \(x=\sqrt{u/v},\ y=\sqrt{uv}\) we get \(|J|=\tfrac1{2v}\), and the area is \(\int_1^2\!\int_1^2\tfrac{1}{2v}\,dv\,du=\tfrac{\ln2}{2}\). The rectangle \([1,2]^2\) in \(uv\) would have area \(1\), but the factor \(\tfrac1{2v}\) corrects it.

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Review the concept: Change of variables in multiple integrals

A change of variables turns the integral of a function \(f\) over a region \(R\) of the \(xy\)-plane into one over a region \(S\) of the \(uv\)-plane, correcting the area with the Jacobian \(J\) of the transformation.

\[\begin{aligned}\iint_R f\,dx\,dy&=\iint_S f(x(u,v),y(u,v))\,|J|\,du\,dv\\J&=\frac{\partial(x,y)}{\partial(u,v)}=\begin{vmatrix}x_u&x_v\\y_u&y_v\end{vmatrix}\end{aligned}\]

More practice problems: change of variables in multiple integrals

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