Exercise · ZW-COMPLETE-METRIC-SPACE-010 · ★★★ Advanced
Let \((X,d)\) be complete and \(d'(x,y)=\min\{d(x,y),1\}\). What holds?
Choose one option.
A \((X,d')\) is not complete because \(d'\) is bounded. B \((X,d')\) is complete only if \(X\) is finite. C \((X,d')\) is complete: both distances have the same Cauchy and convergent sequences. D \(d'\) is not a distance.
Show answer C. \((X,d')\) is complete: both distances have the same Cauchy and convergent sequences.
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Explanation For \(\varepsilon<1\), \(d'(x,y)<\varepsilon\) is equivalent to \(d(x,y)<\varepsilon\). So being Cauchy and converging mean the same with \(d\) and with \(d'\).
A metric space \(X\) is complete if every Cauchy sequence \((x_n)\) in \(X\) converges to a point \(x\) of \(X\). A sequence is Cauchy if its terms eventually get arbitrarily close to one another.
\[(x_n)\ \text{Cauchy}\ \Longrightarrow\ \exists\,x\in X:\ x_n\to x\]
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