Exercise · ZW-COMPLEX-DERIVATIVE-010 · ★★★ Advanced

For \(f(z)=|z|^2\), at which points does \(f'(z)\) exist?

Choose one option.

Show answer
  • B. Only at \(z=0\)

Explanation

Since \(|z|^2=z\bar z\), the quotient at \(z_0\) is \(\bar z_0+\bar h+z_0\bar h/h\). If \(z_0\ne0\), the term \(z_0\bar h/h\) depends on the direction and there is no limit; at \(z_0=0\) the quotient is \(\bar h\to0\). Differentiable only at the origin, with \(f'(0)=0\).

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Review the concept: Complex derivative

The derivative \(f'(z_0)\) of a complex function \(f\) at a point \(z_0\) is the limit of the difference quotient as \(z\) approaches \(z_0\) from any direction in the plane, if that limit exists.

\[f'(z_0)=\lim_{z\to z_0}\frac{f(z)-f(z_0)}{z-z_0}\]

More practice problems: complex derivative

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