Exercise · ZW-COMPLEX-LIMIT-002 · ★☆☆ Basic
Compute \(\lim_{z\to 2i}\dfrac{z^2+4}{z-2i}\).
Choose one option.
Show answer
- C. \(4i\)
Explanation
Since \(z^2+4=(z-2i)(z+2i)\), the quotient equals \(z+2i\) for \(z\neq 2i\), whose limit is \(4i\).
Review the concept: Complex limit
The limit \(L\) of a function \(f\) at \(z_0\) is the complex number that \(f(z)\) gets as close to as desired (\(\varepsilon\)) when \(z\) comes within distance \(\delta\) of \(z_0\), from any direction.
\[\lim_{z\to z_0}f(z)=L\iff\forall\varepsilon>0\ \exists\delta>0:\ 0<|z-z_0|<\delta\Rightarrow|f(z)-L|<\varepsilon\]
More practice problems: complex limit
- ZW-COMPLEX-LIMIT-001 Compute lim _z→ 1+i(z^2+1).
- ZW-COMPLEX-LIMIT-003 Compute lim _z→ i(z^4-1)/(z-i).
- ZW-COMPLEX-LIMIT-004 Compute lim _z→ 0(z^2)/(|z|).
- ZW-COMPLEX-LIMIT-005 If lim _z→ z_0f(z)=1+i and lim _z→ z_0g(z)=2-i, what is lim _z→ z_0f(z)g(z)?
- ZW-COMPLEX-LIMIT-006 About lim _z→ 0(bar z)/(z) it is claimed that:
- ZW-COMPLEX-LIMIT-007 Let f(z)=(x^2-y^2)/(x^2+y^2) with z=x+iy. Which is correct about lim _z→ 0f(z)?
- ZW-COMPLEX-LIMIT-008 The value f(z_0) of a function at the point where the limit is taken:
- ZW-COMPLEX-LIMIT-009 If |f(z)-(2+i)|≤ 3|z| for all z, what follows about lim _z→ 0f(z)?