Exercise · ZW-COMPLEX-LOGARITHM-008 · ★★☆ Intermediate

With \(z=w=-1\), compute \(\operatorname{Log}(zw)-\operatorname{Log}z-\operatorname{Log}w\).

Choose one option.

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  • D. \(-2\pi i\)

Explanation

\(\operatorname{Log}1=0\), but \(\operatorname{Log}(-1)=\pi i\), so the difference is \(0-2\pi i=-2\pi i\). The product rule only holds up to multiples of \(2\pi i\).

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Review the concept: Complex logarithm

A logarithm of a complex number \(z\neq0\) is a complex number \(w\) whose exponential is \(z\).

\[\log z=\ln|z|+i(\arg z+2\pi k),\quad k\in\mathbb{Z}\]

More practice problems: complex logarithm

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