Exercise · ZW-COMPLEX-LOGARITHM-008 · ★★☆ Intermediate
With \(z=w=-1\), compute \(\operatorname{Log}(zw)-\operatorname{Log}z-\operatorname{Log}w\).
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- D. \(-2\pi i\)
Exercise · ZW-COMPLEX-LOGARITHM-008 · ★★☆ Intermediate
Choose one option.
\(\operatorname{Log}1=0\), but \(\operatorname{Log}(-1)=\pi i\), so the difference is \(0-2\pi i=-2\pi i\). The product rule only holds up to multiples of \(2\pi i\).
A logarithm of a complex number \(z\neq0\) is a complex number \(w\) whose exponential is \(z\).