Exercise · ZW-COMPLEX-NTH-ROOT-007 · ★★☆ Intermediate

Find the square roots of \(i\).

Choose one option.

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  • C. \(\pm\frac{\sqrt2}{2}(1+i)\)

Explanation

\(r=1\), \(\theta=\frac\pi2\): \(\cos\frac\pi4+i\sin\frac\pi4=\frac{\sqrt2}2(1+i)\) and its negative. Check: \(\left(\frac{\sqrt2}2(1+i)\right)^2=\frac12\cdot2i=i\).

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Review the concept: Complex nth root

An \(n\)-th root of a complex number \(w\) is a complex number \(z\) whose \(n\)-th power, with \(n\) a positive integer, is \(w\). If \(w\) has modulus \(r\) and argument \(\theta\), its roots are given below.

\[z_k=\sqrt[n]{r}\left(\cos\frac{\theta+2\pi k}{n}+i\sin\frac{\theta+2\pi k}{n}\right),\quad k=0,\dots,n-1\]

More practice problems: complex nth root

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