Exercise · ZW-CONNECTED-SPACE-010 · ★★★ Advanced
Let \(A,B\subseteq X\) be connected (as subspaces ) with \(A\cap B\neq\varnothing\). Then \(A\cup B\) is:
Choose one option.
A not connected B connected C discrete D connected only if \(A=B\)
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Explanation If \(A\cup B\) split into disjoint open sets , the common point would lie in one of them and each connected set \(A\), \(B\) would lie entirely in the one containing that point. So there is no separation.
A topological space \(X\) is connected if it cannot be written as the union of two disjoint nonempty open sets \(U\) and \(V\).
\[X=U\cup V,\ U\cap V=\varnothing\ \Rightarrow\ U=\varnothing\ \text{ or }\ V=\varnothing\]
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