Splitting the integral into two pieces gives \(X(j\omega)=\frac{2}{1+\omega^2}\), which equals \(1\) at \(\omega=1\). The version with a negative sign is wrong because the transform is real and positive.
The continuous Fourier transform \(X(j\omega)\) is a frequency-domain representation of an aperiodic continuous-time signal \(x(t)\), assigning to each frequency \(\omega\) its spectral content.