Fourier series and transform · Definition

Continuous Fourier transform

signal processingfourier series and transform

The Fourier transform extends the Fourier series to non-periodic signals, moving from a discrete spectrum to a continuous one. It allows analyzing finite-energy signals in the frequency domain.

Definition

The continuous Fourier transform \(X(j\omega)\) is a frequency-domain representation of an aperiodic continuous-time signal \(x(t)\), assigning to each frequency \(\omega\) its spectral content.

\[X(j\omega)=\int_{-\infty}^{\infty}x(t)e^{-j\omega t}\,dt\]

If \(x(t)\) is absolutely integrable, its transform exists and the inverse \(x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}X(j\omega)e^{j\omega t}\,d\omega\) recovers the signal. The transform is linear, and a time shift \(x(t-t_0)\) produces a phase factor \(e^{-j\omega t_0}\) in \(X(j\omega)\) without changing its magnitude. Moreover, time-domain convolution corresponds to frequency-domain multiplication.

Consider the rectangular pulse \(x(t)=1\) for \(|t|<T_1\) and \(0\) otherwise. Direct integration gives \(X(j\omega)=\frac{2\sin(\omega T_1)}{\omega}\), whose value at \(\omega=0\) is \(2T_1\), equal to the area of the pulse. This shows how a short-duration signal has a wide spectrum.

A typical error is forgetting the negative sign in the kernel exponential, using \(e^{j\omega t}\) in the forward transform. This flips the spectrum in frequency and gives wrong results for non-symmetric signals. Always check the sign convention before integrating.

Think about it

What happens to \(X(j\omega)\) when the signal is stretched in time, \(x(at)\) with \(0<a<1\)?

The spectrum is compressed in frequency by the factor \(a\) and its amplitude is multiplied by \(1/a\), since the signal is stretched in time.

Exercises 10

References

  • Alan V. Oppenheim, Alan S. Willsky, Signals and Systems, 2nd edition, Pearson, 1996.
  • Alan V. Oppenheim, Ronald W. Schafer, Discrete-Time Signal Processing, 3rd edition, Pearson, 2010.