With \(y'=x+y\) and \(y(0)=1\), follow the field with horizontal steps of \(0.1\) (use the slope at the start of each step). What is the estimate of \(y(0.2)\)?
At \((0,1)\) the slope is \(1\), so \(y(0.1)\approx 1.1\). At \((0.1,1.1)\) the slope is \(1.2\), so \(y(0.2)\approx 1.1+0.12=1.22\). Reusing the first slope would give the typical error \(1.20\).