Higher-order linear equations · Definition

Superposition principle

differential equationshigher order

Before you start you need to know

It turns a few known solutions into a whole family of solutions, and is why linear equations are solved by assembling pieces.

Definition

It states that if \(y_1\) and \(y_2\) are solutions of a linear homogeneous equation \(L[y]=0\), every linear combination of them with constants \(c_1,c_2\) is also a solution.

\[L[c_1y_1+c_2y_2]=c_1L[y_1]+c_2L[y_2]=0\]

Here \(L[y]\) is the left-hand side of the equation, for example \(L[y]=y''+py'+qy\). The key is that \(L\) is linear: \(L[c_1y_1+c_2y_2]=c_1L[y_1]+c_2L[y_2]\), a property inherited from the derivative. If \(L[y_1]=L[y_2]=0\), the result is \(0\), and the combination is still a solution.

The principle fails in two situations. If the equation is nonhomogeneous, \(y=0\) is not a solution and a multiple of a solution drifts from the right-hand side: \(y=1\) solves \(y''+y=1\), but \(y=2\) gives \(2\). If it is nonlinear, like \(y'=y^2\), it does not work either. In contrast, the difference of two solutions of \(L[y]=g\) does solve the homogeneous equation.

With \(e^{2t}\) and \(e^{3t}\) in \(y''-5y'+6y=0\), every function \(c_1e^{2t}+c_2e^{3t}\) is a solution, and the two constants let us adjust \(y(0)\) and \(y'(0)\). What remains is to know when two solutions suffice to generate all of them; the Wronskian decides that.

Think about it

If \(y_1\) and \(y_2\) solve \(y''+y=0\), does \(y_1y_2\) solve that equation?

In general no: superposition covers linear combinations, not products. For \(y_1=y_2=\sin t\), \((\sin^2t)''+\sin^2t=2\cos2t+\sin^2t\neq0\).

Exercises 10

References

  • William E. Boyce, Richard C. DiPrima, Douglas B. Meade, Elementary Differential Equations and Boundary Value Problems, 12th edition, Wiley, 2021. §3.2
  • Dennis G. Zill, A First Course in Differential Equations with Modeling Applications, 11th edition, Cengage, 2018. §4.1