Exercise · ZW-DOUBLE-INTEGRAL-002 · ★☆☆ Basic

Find the volume of the solid under the plane \(z=4\) and above the disk \(D\) of radius \(2\) centered at the origin, i.e. \(\iint_D 4\,dA\).

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  • C. \(16\pi\)

Explanation

The integral of a constant is the constant times the area: \(4\cdot\pi\cdot2^2=16\pi\). This is the volume of a cylinder of radius \(2\) and height \(4\).

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Review the concept: Double integral

The double integral of a function \(f\) over a region \(D\) of the plane is the limit of the sums of the values of \(f\) times the area \(\Delta A\) of ever finer cells covering \(D\).

\[\iint_D f(x,y)\,dA=\lim_{\max\Delta A_i\to0}\sum_i f(x_i^*,y_i^*)\,\Delta A_i\]

More practice problems: double integral

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