Exercise · ZW-EXISTENCE-AND-UNIQUENESS-THEOREM-006 · ★★☆ Intermediate
For \(y'=x+y^2\), can two different solutions cross?
Choose one option.
A Yes, at a point where both have the same slope B Yes, whenever they solve different problems C No, because exactly one solution passes through each point D Yes, because the equation is not linear
Show answer C. No, because exactly one solution passes through each point
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Explanation Since \(f=x+y^2\) and \(f_y=2y\) are continuous on the whole plane, exactly one solution passes through each point; if two curves crossed, there would be two solutions through that point.
The existence and uniqueness theorem guarantees that an initial value problem has a unique solution near the initial point, if the equation and its partial derivative with respect to the unknown are continuous there.
\[f,\ \frac{\partial f}{\partial y}\ \text{continuous near }(x_0,y_0)\ \Longrightarrow\ \text{a unique solution}\]
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