Exercise · ZW-EXISTENCE-AND-UNIQUENESS-THEOREM-006 · ★★☆ Intermediate

For \(y'=x+y^2\), can two different solutions cross?

Choose one option.

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  • C. No, because exactly one solution passes through each point

Explanation

Since \(f=x+y^2\) and \(f_y=2y\) are continuous on the whole plane, exactly one solution passes through each point; if two curves crossed, there would be two solutions through that point.

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Review the concept: Existence and uniqueness theorem

The existence and uniqueness theorem guarantees that an initial value problem has a unique solution near the initial point, if the equation and its partial derivative with respect to the unknown are continuous there.

\[f,\ \frac{\partial f}{\partial y}\ \text{continuous near }(x_0,y_0)\ \Longrightarrow\ \text{a unique solution}\]

More practice problems: existence and uniqueness theorem

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