Exercise · ZW-EXPONENTIAL-GROWTH-AND-DECAY-004 · ★★☆ Intermediate

A substance has a half-life of 5 years and satisfies \(y'=ky\). What is \(k\)?

Choose one option.

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  • D. \(k=-\tfrac{\ln2}{5}\)

Explanation

From \(e^{5k}=\tfrac12\) we get \(k=-\tfrac{\ln2}{5}\), negative because it is decay.

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Review the concept: Exponential growth and decay

A quantity \(y\) with initial value \(y_0\) grows or decays exponentially when its rate of change is proportional to itself, with constant \(k\): it grows if \(k>0\), decays if \(k<0\).

\[y'=ky\;\Longrightarrow\; y(t)=y_0\,e^{kt}\]

More practice problems: exponential growth and decay

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