Exercise · ZW-FIRST-ORDER-LINEAR-EQUATION-007 · ★★☆ Intermediate
Solve \(y'+y=0\), \(y(0)=5\).
Choose one option.
Show answer
- B. \(y=5e^{-x}\)
Explanation
The general solution is \(y=Ce^{-x}\) and \(y(0)=C=5\).
Review the concept: First-order linear equation
A first-order linear equation is a differential equation in which \(y\) and \(y'\) appear to the first power, with a coefficient \(p\) and a free term \(q\) that depend only on \(x\).
\[y'+p(x)\,y=q(x)\]
More practice problems: first-order linear equation
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- ZW-FIRST-ORDER-LINEAR-EQUATION-003 Find the general solution of y'+y=0.
- ZW-FIRST-ORDER-LINEAR-EQUATION-004 The equation x y'+2y=x^2, with x>0, is brought to standard form by dividing by x. What is p(x)?
- ZW-FIRST-ORDER-LINEAR-EQUATION-005 The equation y'+2y=4 has a constant solution. Which one?
- ZW-FIRST-ORDER-LINEAR-EQUATION-006 Find the general solution of y'+2xy=0.
- ZW-FIRST-ORDER-LINEAR-EQUATION-008 Which of these functions is a solution of y'+y=x?
- ZW-FIRST-ORDER-LINEAR-EQUATION-009 The general solution of y'+y=x is y=x-1+Ce^-x. Which is the solution with y(0)=0?
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