Exercise · ZW-FUNDAMENTAL-THEOREM-OF-ALGEBRA-005 · ★★☆ Intermediate
The roots of \(z^3-6z^2+11z-6\) add up to:
Choose one option.
Show answer
- C. \(6\)
Exercise · ZW-FUNDAMENTAL-THEOREM-OF-ALGEBRA-005 · ★★☆ Intermediate
Choose one option.
With \(p=\prod(z-z_k)\), the coefficient of \(z^2\) is \(-\sum z_k\). Here it is \(-6\), so the sum is \(6\) (roots \(1,2,3\)).
Every non-constant polynomial \(p\) with complex coefficients, of degree \(n\), has at least one root in \(\mathbb{C}\); hence it splits into \(n\) linear factors \(z-z_k\), with leading coefficient \(a_n\).
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