Exercise · ZW-INFINITUDE-OF-PRIMES-006 · ★★☆ Intermediate

Compute \(N = 2\cdot 3\cdot 5\cdot 7\cdot 11 + 1\) and determine its smallest prime divisor.

Choose one option.

Show answer
  • C. 2311, because \(N\) is prime

Explanation

The product is \(2310\) and \(N = 2311\), which is prime. The option saying 11 divides \(N\) is wrong, because \(N\) leaves remainder 1 when divided by 11.

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Review the concept: Infinitude of primes

The infinitude of primes is Euclid's theorem stating that the set of prime numbers is infinite: given any finite list of primes \(p_1,\dots,p_n\), there is a prime not on it.

\[p\mid p_1p_2\cdots p_n+1\ \Longrightarrow\ p\neq p_i\ \text{for all } i\]

More practice problems: infinitude of primes

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