Exercise · ZW-INFINITUDE-OF-PRIMES-007 · ★★☆ Intermediate

What is the remainder of \(2\cdot 3\cdot 5\cdot 7\cdot 11\cdot 13 + 1\) when divided by \(7\)?

Choose one option.

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  • B. 1

Explanation

The product contains the factor \(7\), so it is a multiple of \(7\) and adding \(1\) leaves remainder \(1\). The option giving 0 would mean \(7\) divides the number, which is false.

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Review the concept: Infinitude of primes

The infinitude of primes is Euclid's theorem stating that the set of prime numbers is infinite: given any finite list of primes \(p_1,\dots,p_n\), there is a prime not on it.

\[p\mid p_1p_2\cdots p_n+1\ \Longrightarrow\ p\neq p_i\ \text{for all } i\]

More practice problems: infinitude of primes

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