Exercise · ZW-LAGRANGE-MULTIPLIERS-006 · ★★☆ Intermediate

Find the maximum value of \(f(x,y)=xy\) on the circle \(x^2+y^2=8\).

Choose one option.

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  • A. 4

Explanation

The equations \(y=2\lambda x\), \(x=2\lambda y\) give \(x^2=y^2\), so \(x=\pm y\) and \(2x^2=8\). The points \((2,2)\) and \((-2,-2)\) give \(4\); the other two give \(-4\).

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Review the concept: Lagrange multipliers

The method of Lagrange multipliers finds the extrema of a function \(f\) on the curve \(g=k\) among the points where the gradient of \(f\) is a multiple \(\lambda\) of the gradient of \(g\).

\[\nabla f=\lambda\,\nabla g,\qquad g=k\]

More practice problems: lagrange multipliers

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