Exercise · ZW-LINEAR-DIOPHANTINE-EQUATION-007 · ★★☆ Intermediate
Given the particular solution \((x_0,y_0)=(2,-1)\) of \(4x+6y=2\), what is the general solution with \(t\in\mathbb{Z}\)?
Choose one option.
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- A. \(x=2+3t,\ y=-1-2t\)
Exercise · ZW-LINEAR-DIOPHANTINE-EQUATION-007 · ★★☆ Intermediate
Choose one option.
Since \(\gcd(4,6)=2\), the steps are \(6/2=3\) in \(x\) and \(-4/2=-2\) in \(y\). Flipping the sign of the step in \(y\) breaks the equation, and a unit step does not preserve it either.
A linear Diophantine equation is \(ax+by=c\) with integer coefficients, where we seek integer pairs \(x,y\) as solutions.
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