Exercise · ZW-LOGISTIC-MODEL-006 · ★★☆ Intermediate
For \(P'=P\left(1-\frac{P}{10}\right)\) with \(P(0)=1\), the solution is \(P(t)=\dfrac{10}{1+9e^{-t}}\). What is \(P(\ln 9)\)?
Choose one option.
Show answer
- A. \(5\)
Explanation
\(e^{-\ln 9}=1/9\), so \(P(\ln9)=\dfrac{10}{1+9\cdot\frac19}=\dfrac{10}{2}=5\).
Review the concept: Logistic model
Model of a population \(P\) with intrinsic rate \(r>0\), carrying capacity \(K>0\) and initial population \(P_0\): it grows almost exponentially at first and levels off at \(K\).
\[P'=rP\left(1-\frac{P}{K}\right)\;\Longrightarrow\; P(t)=\frac{K}{1+\left(\frac{K}{P_0}-1\right)e^{-rt}}\]
More practice problems: logistic model
- ZW-LOGISTIC-MODEL-001 Find the equilibrium points of P'=0.5 P(1-(P)/(100)).
- ZW-LOGISTIC-MODEL-002 The equation P'=0.2 P-0.002 P^2 is logistic. What is its carrying capacity K?
- ZW-LOGISTIC-MODEL-003 In P'=0.03 P(1-(P)/(500)), what are r and K?
- ZW-LOGISTIC-MODEL-004 In the logistic model, if 0<P<K, how does P evolve?
- ZW-LOGISTIC-MODEL-005 For P'=0.4 P(1-(P)/(200)), at what population is the growth rate P' largest?
- ZW-LOGISTIC-MODEL-007 With r=0.1 and K=100, a population P=300 exceeds the carrying capacity. What is P' at that moment?
- ZW-LOGISTIC-MODEL-008 With r=tfrac12, K=1000 and P_0=100, at what time does P reach K/2?
- ZW-LOGISTIC-MODEL-009 Two logistic populations have the same r and K=100, but P_0=5 and P_0=60. What happens in the long…