Exercise · ZW-MATRIX-MULTIPLICATION-005 · ★★☆ Intermediate

For \(A=\begin{pmatrix}1&1\\0&1\end{pmatrix}\) and \(B=\begin{pmatrix}1&0\\1&1\end{pmatrix}\), compute \(AB-BA\).

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  • A. \(\begin{pmatrix}1&0\\0&-1\end{pmatrix}\)

Explanation

\(AB=\begin{pmatrix}2&1\\1&1\end{pmatrix}\) and \(BA=\begin{pmatrix}1&1\\1&2\end{pmatrix}\); their difference is nonzero, so the product is not commutative.

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Review the concept: Matrix multiplication

The product \(AB\) of two matrices \(A\) and \(B\), when \(A\) has as many columns as \(B\) has rows, is the matrix whose \((i,j)\) entry combines row \(i\) of \(A\) with column \(j\) of \(B\).

\[(AB)_{ij}=\sum_{k=1}^{n}a_{ik}b_{kj}\]

More practice problems: matrix multiplication

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