Exercise · ZW-MATRIX-MULTIPLICATION-005 · ★★☆ Intermediate
For \(A=\begin{pmatrix}1&1\\0&1\end{pmatrix}\) and \(B=\begin{pmatrix}1&0\\1&1\end{pmatrix}\), compute \(AB-BA\).
Choose one option.
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- A. \(\begin{pmatrix}1&0\\0&-1\end{pmatrix}\)
Exercise · ZW-MATRIX-MULTIPLICATION-005 · ★★☆ Intermediate
Choose one option.
\(AB=\begin{pmatrix}2&1\\1&1\end{pmatrix}\) and \(BA=\begin{pmatrix}1&1\\1&2\end{pmatrix}\); their difference is nonzero, so the product is not commutative.
The product \(AB\) of two matrices \(A\) and \(B\), when \(A\) has as many columns as \(B\) has rows, is the matrix whose \((i,j)\) entry combines row \(i\) of \(A\) with column \(j\) of \(B\).
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