Exercise · ZW-MODULAR-INVERSE-006 · ★★☆ Intermediate
Find the inverse of \(5\) modulo \(11\).
Choose one option.
Show answer
- C. \(9\)
Explanation
Since \(5\cdot 9=45=4\cdot 11+1\), the inverse is \(9\). With \(7\), the product \(35\) leaves remainder \(2\) modulo \(11\), so it fails.
Review the concept: Modular inverse
The modular inverse of an integer \(a\) modulo \(m\) is an integer \(b\) whose product with \(a\) is congruent to 1 modulo \(m\).
\[ab \equiv 1 \pmod{m}\]
More practice problems: modular inverse
- ZW-MODULAR-INVERSE-001 What is the necessary and sufficient condition for a to have an inverse modulo m?
- ZW-MODULAR-INVERSE-002 Does 2 have an inverse modulo 4?
- ZW-MODULAR-INVERSE-003 State the uniqueness property of the modular inverse modulo m.
- ZW-MODULAR-INVERSE-004 Which integer b satisfies 3b≡ 1pmod5?
- ZW-MODULAR-INVERSE-005 Which of these congruences has a solution in b?
- ZW-MODULAR-INVERSE-007 Which pair of numbers are inverses of each other modulo 10?
- ZW-MODULAR-INVERSE-008 Solve 3x≡ 2pmod7 using the inverse of 3.
- ZW-MODULAR-INVERSE-009 If b is an inverse of a modulo m and c≡ apmodm, what holds?